If 2sin60°. cos10° = cosA + cosB. Then find the value of B ?
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We know that-
2cosX cosY = cos(X+Y) + cos(X-Y)
Now,
2cos60°cos 10º = cosA + cosB
⇒ cosA + cosB = Cos(60+10)° + cos(60-10)°
⇒ cosA + cosB = Cos(70)° + cos(50)°
∴ On compairing both sides of the equation, we get
A = 70° ; B = 50°
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