Question

if 2sinA=1=2×2cosB and 180/2, ×180<A<180, 3×180/2<B<2×180, Then find the value of tanA+tanB /cosA- cosB​

Answer 1

Answer:

the sinA =12 and the value of CosA=3

Answer 2

Step-by-step explanation:

Illustration 1:If A + B = π /2 and B + C = A, then tan A equals (2001)

1. 2 (tan B + tan C) 2. tan B + tan C

3. tan B + 2tan C 4. 2 tan B + tan C

Solution: It is given in the question that A + B = π /2 and B + C = A.

Hence, A = π /2 – B

So, tan A = tan (π /2 – B) which gives tan A = cot B

Now, tan Atan B = 1

Also, B + C = A

So, C = A – B

tan C = tan (A – B)

also, tan C = (tan A – tanB)/ (1 + tan A tan B)

tan C = (tan A – tanB)/ (1 + 1)

Therefore, 2 tan C = tan A – tan B

Hence, tan A =tanB + 2 tan C