Question

If 2sinA = 1 = √2cos B and π/2 <A< π,3π/2 < B< 2π, then find the value of tanA+tanB /Cos A - cos B​

Answer 1

Step-by-step explanation:

2SinA=1=√2CosB

SinA=1/2

A=30(Sin30=1/2)

√2CosB=1

CosB=1/√2

B=45(Cos45=1/√2)

tanA+tanB/CosA-CosB

tan30+tan45/Cos30-Cos45

1/√3+1/√3/2-1/√2

1/√3+2/√3-1/√2

3/√3-1/√2

√3-1/√2

$\sqrt{6} - 1 \div \sqrt{2}$

$\sqrt{12} - \sqrt{2} \div 2$

Hope it helps you