If 2sina/1+cosa+sina=y then prove that 1-cosa+sina/1+sina is also equal to y
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Given y = 2sinA1+cosA+sinA
Let K = 1−cosA+sinA1+sinAK(1+sinA)
=(1−cosA+sinA)×1+cosA+sinA1+cosA+sinA
=((1+sinA)+cosA)((1+sinA)−cosA)1+cosA+sinA=(1+sinA)2−(cosA)21+cosA+sinA
=(1+sinA)2−(1−sin2A)1+cosA+sinA
=(1+sinA)2−(1−sinA)(1+sinA)1+cosA+sinA
=(1+sinA)[1+sinA−1+sinA]1+cosA+sinASo K(1+sinA)=
(1+sinA)[2sinA]1+cosA+sinA
or
K = 2sinA1+cosA+sinA=ySO K= 1−cosA+sinA1+sinA = y
Hence proved
Let K = 1−cosA+sinA1+sinAK(1+sinA)
=(1−cosA+sinA)×1+cosA+sinA1+cosA+sinA
=((1+sinA)+cosA)((1+sinA)−cosA)1+cosA+sinA=(1+sinA)2−(cosA)21+cosA+sinA
=(1+sinA)2−(1−sin2A)1+cosA+sinA
=(1+sinA)2−(1−sinA)(1+sinA)1+cosA+sinA
=(1+sinA)[1+sinA−1+sinA]1+cosA+sinASo K(1+sinA)=
(1+sinA)[2sinA]1+cosA+sinA
or
K = 2sinA1+cosA+sinA=ySO K= 1−cosA+sinA1+sinA = y
Hence proved
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