Question

If √2sinA=1, find the value of sec²A-cosec²A

Answer 1

Answer:

√2sinA=1

SinA=1/√2

Sin A = sin45°

Therefore , comparing both side

A = 45°

=sec²A - cosec²A

=sec²45° - cosec²45°

=(√2)² - (√2)²

= 2 - 2

= 0

Hope it helps you!!

Answer 2

Answer:0

Step-by-step explanation:

Given that, √2SinA=1

Or, SinA=(1/√2)=Sin45°

To find: Sec^2A-Cosec^2A=?

Now, Cos^2A=(1-Sin^2A)={1-(1/2)}=1/2

Now,Sec^2A-Cosec^2A={1/cos^2A}-{1/Sin^2A}

={1/(1/2)}-{1/(1/2)} =2-2=0