Question

if 2sinA-√3=0 find 1+tan2A​

Answer 1

Step1:2SinA-root3=0 so;;SinA=root3/2 then SinA=Sin60deg then A=60 now 1+tan2A=? Step-2:: tan2A= tan2(60)=tan 120 = - root3. So 1+tan2A = 1+( - root3 ) =1- root3