if 2sinA=5 then find tanA
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Let sinA=5/2
We know that sinA=P/H
So P=5 and H=2
Now by using Pythagoras we can calculate Base
And tanA=P/B
We know that sinA=P/H
So P=5 and H=2
Now by using Pythagoras we can calculate Base
And tanA=P/B
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