Question

If 2sinAcosA= 1 then what is the value of sinA–cosA

Answer 1

Step-by-step explanation:

(sinA+cosA)^2=sin^ (2)A+cos^(2)A+2×sinAcosA

Sin^(2)A+cos^(2)A=1 by trigonometric identities also 2 sinA cosA =sin2A

And sinA+cosA=1 by given question

Therefore the equation becomes

Sin2A=1^(2) -1

Sin2A=0

2A=sin inverse(0)

A=0

mrk me as BRAINLIEST

Answer 2

Since sin2θ=2sinθcosθ

it implies sin2A=1

So, the value of A=pie/4

Thus sinA-cosA=sin(pie/4) - cos(pie/4)

=0