if 2sinsqx-cossqx=2 find the value of x
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2 sin² x- cos² x=2
2 sin² x - cos ² x= 2*1
2 sin² x - cos²x=2(sin² x+ cos²x)
2 sin² x-cos²x=2sin²x+2cos²x
0=3 cos²x
cos²x=0
cos x=0
cos x=cos 90
x=90°
2 sin² x - cos ² x= 2*1
2 sin² x - cos²x=2(sin² x+ cos²x)
2 sin² x-cos²x=2sin²x+2cos²x
0=3 cos²x
cos²x=0
cos x=0
cos x=cos 90
x=90°
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