if 2t=2.2-6s and 5s=2t+1.1 then s=?
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let
6s=2.29-2t-(1)
then
s=2.2-2t/6
5s=2t+1.1
then
s=2t+1.1/5
equate s and s
2.2-2t/6=2t+1.1/5
cross multiply
11-10t=12t+6.6
11-6.6=12t+10t
4.4=22t
t=4.4/22
t=0.2
put t=0.2 in equation (1),then we get
6s=2.2-2*0.2
6s=2.2-0.4
6s=1.8
s=1.8/6
s=0.3
therefore s=0.3
6s=2.29-2t-(1)
then
s=2.2-2t/6
5s=2t+1.1
then
s=2t+1.1/5
equate s and s
2.2-2t/6=2t+1.1/5
cross multiply
11-10t=12t+6.6
11-6.6=12t+10t
4.4=22t
t=4.4/22
t=0.2
put t=0.2 in equation (1),then we get
6s=2.2-2*0.2
6s=2.2-0.4
6s=1.8
s=1.8/6
s=0.3
therefore s=0.3
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