Question

if 2tan^2(thetha) = sec^2(theth)
find compressive value of thetha.?

Answer 1

Solution:-

$2 { \tan }^{2} \theta = { \sec }^{2} \theta \\ 2 { \tan }^{2} \theta = 1 + { \tan }^{2} \theta \\ { \tan }^{2} \theta = 1 \\ { \tan }^{2} \theta = { \tan }^{2} \frac{\pi}{4} \\ \theta = n\pi( + - ) \frac{\pi}{4} ans$