If 2to the power a=3to the power b =6 to the power -c then find the value of 1/a+1/b+1/c
Answers
Answered by
1
Step-by-step explanation:
Let 2^a=3^b=6^c =k
2 = k^(1/a), 3 = k^(1/b) and 6= k^(1/c)
2*3=6
k^(1/a)*k^(1/b) = k^(1/c)
k^(1/a +a/b)= k^(1/c)
1/a +a/b = 1/c
a+b/ab = 1/c
c= ab/a+b
Similar questions