Question

If (2x−1)(2x−1)  is exactly divides 6x2+ax−46x2+ax−4  and bx2−11x+3,bx2−11x+3,  then the value of b2−a2+a−bb2−a2+a−b  is ​

Answer 1

6x3 - 17x2 + 11x - 2

Simplify ———————————

2x + 3

Checking for a perfect cube :

3.1 6x3 - 17x2 + 11x - 2 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 6x3 - 17x2 + 11x - 2

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 11x - 2

Group 2: 6x3 - 17x2

Pull out from each group separately :

Group 1: (11x - 2) • (1)

Group 2: (6x - 17) • (x2)