Question

If 2x – 1, 2x – 3 and x + 4 are in A.P. find x

Answer 1

Answer:

x=9

Step-by-step explanation:

solⁿ

since 2x-1, 2x-3 and x+4 are in AP,

then

a=2x-1

d=2x-3-(2x-1)

=2x-3-2x+1

=-2

l=x+4=tn

n=3

now,

tn=a+(n-1)d

x+4=2x-1 +(3-1)×(-2)

x+4=2x-1-4

2x-x=4+4+1

∴x=9

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Answer 2

If 2x – 1, 2x – 3 and x + 4 are in AP then x = 9

Given :

2x – 1, 2x – 3 and x + 4 are in AP

To find :

The value of x

Solution :

Step 1 of 2 :

Form the equation

Here it is given that 2x – 1, 2x – 3 and x + 4 are in AP

By the given condition

$\displaystyle \sf{ 2(2x - 3) = (2x - 1) + (x + 4)}$

Step 2 of 2 :

Find the value of x

We know that if a , b , c are in AP then 2b = a + c

Thus we get

$\displaystyle \sf{ 2(2x - 3) = (2x - 1) + (x + 4)}$

$\displaystyle \sf{ \implies 4x - 6 = 2x - 1+ x + 4}$

$\displaystyle \sf{ \implies 4x - 6 = 3 x + 3}$

$\displaystyle \sf{ \implies 4x - 3 x = 6+ 3}$

$\displaystyle \sf{ \implies x = 9}$

The value of x = 9

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