Question

If 2x-1=4/3(4x+1) then the value of x is?​

Answer 1

Given:

• If 2x-1= $\sf\frac{4}{3}$(4x+1) then the value of x is?

To find:

• Value of x

Solution:

$:\implies \sf{2x - 1 = \frac{4}{3} (4x + 1)}$

$: \implies \sf{(2x - 1) 3 = 4(4x + 1)}$

$: \implies \sf{6x - 3 = 16x + 1}$

$: \implies \sf{6x - 16x = 3 + 1}$

$: \implies \sf{ - 10x = 4}$

$:\implies \large{\sf{x = \frac{4}{10} }}$

$:\implies \underline{\boxed{\frak{{x = \frac{2}{5} }}}} \: \pink{ \bigstar}$

• Hence, the value of $\sf{x= \frac{4}{3}}$

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