If 2x+1 is a factor of (3b-1) x^3 + (b-2 ) then find b
Answers
Answered by
3
2x+1=0 then x=-1/2
(3b-1) x^3 + (b-2 )=0
substitue the value of x=-1/2 in above equation
(3b-1)(-1/2)^3+b-2=0
-(3b-1)+8(b-2)=0
-3b+1+8b-16=0
5b-15=0
5b=15
b=3
(3b-1) x^3 + (b-2 )=0
substitue the value of x=-1/2 in above equation
(3b-1)(-1/2)^3+b-2=0
-(3b-1)+8(b-2)=0
-3b+1+8b-16=0
5b-15=0
5b=15
b=3
Similar questions