Question

if (2x+1) is a factor of f(x) =2x^3+ax^2+16x+6 show that a=9

Answer 1

Step-by-step explanation:

Step by step solution :

STEP

1

:

Equation at the end of step 1

(((2 • (x3)) - 11x2) + 16x) - 6 = 0

STEP

2

:

Equation at the end of step

2

:

((2x3 - 11x2) + 16x) - 6 = 0

STEP

3

:

Checking for a perfect cube

3.1 2x3-11x2+16x-6 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 2x3-11x2+16x-6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 16x-6

Group 2: 2x3-11x2

Pull out from each group separately :

Group 1: (8x-3) • (2)

Group 2: (2x-11) • (x2)

Bad news !! Factoring by pulling out fails :