If (2x+1) is afactor of 6x cube + 5x square + ax -2 find the value of a
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Answer:
a=-3
Step-by-step explanation:
1. Do long division, (6x^3 + 5x + ax - 2)/(2x+1).
2. As (2x+1) is factor of 6x^3 + 5x + ax - 2 equation, there will be no remainder exist.
3. By completing the comparison among the part x and the integer part, value of a can be obtained.
4. Refer to the picture for detail working.
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Answered by
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Step-by-step explanation:
answer. a=-3
explanation is given above check it
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