Math, asked by rohitbhai8981, 1 year ago

If (2x+1) is afactor of 6x cube + 5x square + ax -2 find the value of a

Answers

Answered by Yeeyong0531
0

Answer:

a=-3

Step-by-step explanation:

1. Do long division, (6x^3 + 5x + ax - 2)/(2x+1).

2. As (2x+1) is factor of 6x^3 + 5x + ax - 2 equation, there will be no remainder exist.

3. By completing the comparison among the part x and the integer part, value of a can be obtained.

4. Refer to the picture for detail working.

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Answered by purohitseema09
0

Step-by-step explanation:

answer. a=-3

explanation is given above check it

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