Question

if 2x+1 is factor of (3b+2)x3+(b-1) then find b​

Answer 1

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Given that 2x+1 is the factor of

(3b+2)x3+(b-1)

so , 2x+1= 0

=> 2x = -1

=> x= -1/2

Now , f(x)= (3b+2)x3+(b-1)

so,. f(-1/2) = (3b+2)×(-1/2)3+(b-1)

= (3b+2)×(-3/2)+(b-1)

= -9b /2 -6 /2 +b-1

= -9b - 6 + 2b -2

= -7b - 8

Now for finding the value of b

-7b-8= 0

=> -7b = 8

=> -b = 8/7

=> b = -8/7

Answer 2

Step-by-step explanation:

2x+1=0-->x=-1/2

x=-1/2 subtitution to (3b+2)x³+(b-1) equal to 0

(3b+2)(-1/2)³+(b-1)=0

(-3b-2)/8 +(b-1)=0

-3b-2+8b-8=0

-3b+8b=8+2

5b=10

b=2