If |2x-1|is less than 0 then the value of x is
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Step-by-step explanation:
When x is less than the given value i.e. 1/2 in this case and when x is greater than the given value.
So,
2x - 1 < 0 (since x is greater than 1/2 , applying modulus is futile)
2x < 1
x < 1/2 (or equal to 1/2)
The common solution in our assumption and the equation is x = 1/2. Therefore the first solution is x = 1/2
Now,
-2x + 1 < 0
-2x < -1
x > 1/2 (or equal to it)
The common solution again is x = 1/2
Final solution = intersection of solution 1 and 2
X = 1/2
Answered by
0
Answer:
If |2x-1|is less than 0 then the value of x is
Step-by-step explanation:
0
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