Question

If |2x-1 |<_0, then the value of x is


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Answer 1

Answer:

When x is less than the given value i.e. 1/2 in this case and when x is greater than the given value.

So,

2x - 1 < 0 (since x is greater than 1/2 , applying modulus is futile)

2x < 1

x < 1/2 (or equal to 1/2)

The common solution in our assumption and the equation is x = 1/2. Therefore the first solution is x = 1/2

Now,

-2x + 1 < 0

-2x < -1

x > 1/2 (or equal to it)

The common solution again is x = 1/2

Final solution = intersection of solution 1 and 2

X = 1/2

Explanation:

answer is x=1/2

Answer 2

Answer:

When x is less than the given value i.e. 1/2 in this case and when x is greater than the given value.

So,

2x - 1 < 0 (since x is greater than 1/2 , applying modulus is futile)

2x < 1

x < 1/2 (or equal to 1/2)

The common solution in our assumption and the equation is x = 1/2. Therefore the first solution is x = 1/2

Now,

-2x + 1 < 0

-2x < -1

x > 1/2 (or equal to it)

The common solution again is x = 1/2

Final solution = intersection of solution 1 and 2

X = 1/2