If 2x=12 for 3x+2y=23, then find the value of y
Answers
nakabuti mo sa ibang Tao
Answer:
let us your first
Step-by-step explanation:
let us assume your first equation as =>
2x + 0y = 12. ,; (cuz, it still equals to 2x = 12 as 0y will become "0" ;
2nd equation as ==> 3x + 2y = 23
So by using Elimination Method,...
we multiply eq 1 to 3 (eq1 * 3)
and eq 2 to 2(eq2 *2)
means--- (2x + 0y = 12) * 3
and ( 3x + 2y = 23)* 2
we are doing this because we want to equal the coefficient of "x" in both equations.. now,
eq 1==> 6x + 0y = 36
as (2x *3) = 6x ; (0y * 3) = 0 ; (12 *3) = 36,,,
eq 2==> 6x + 4y = 46
as (3x *2)= 6x ; (2y*2)=4y ; (23*2)=46,,,,
now we simply substrate eq1 from eq2 .as,
(6x - 6x) + (4y - 0y) = (46 - 36)....
and answer will automatically comes in our way..
0 + 4y = 10 ==> 4y = 10
y = 10/4 ==> |y = 2.5|
now we simply put this value in equation 2 as..
6x + 4*(2.5) = 46
6x + 10 = 46
6x = 46 -10
6x = 36
x = 36/6
and yippee now you can do what's next :)
it's a secret <[ ° = ° ]>. x = 6
hence x = 6 and y = 2.5
enjoyyyyyyyyyy