if (2x^2+3x-5)(x+2)=ax^3+bx^2+cx+d, then ac-bd=?
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2x^3+4x^2+3x^2+6x-5x-10=2x^3+7x^2+x-10=ax^3+bx^2+cx+d
a=2: b=7; c=-1; d=-10
ac-bd=2-7(-10)=2+70=72
a=2: b=7; c=-1; d=-10
ac-bd=2-7(-10)=2+70=72
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