Question

If (2x+2), (4x+1), (3x+4) and (6x+1) are in propotion, find the value of x ​

Answer 1

Answer:

6x - 10

Step-by-step explanation:

The tricky part is rewriting g(x + 2) as g(x) instead.

Start by substituting u = x + 2

u = x + 2

x = u - 2

Now we have:

g(u) = 3(u - 2) + 1

g(u) = 3u - 6 + 1

g(u) = 3u - 5

We have the function g with a single variable. So we could replace it back to x:

g(x) = 3x - 5

So the question becomes much simpler:

f(x) = 2x

g(x) = 3x - 5

To find f(g(x)), just put in g(x) = 3x - 5 into f(x)

f(x) = 2x

f(g(x)) = 2 * g(x)

f(g(x)) = 2(3x - 5)

f(g(x)) = 6x - 10

Answer:

6x - 10

g(x+2)=3x+1

Answer 2

Answer: x= -2/5

Step-by-step explanation:

here,

(2x +2) : (4x +1) :: (3x+4) : (6x+1)

=> (2x +2) / (4x+1) = (3x+4) / (6x+1)

After Cross Multiplication..

=> (2x +2) (6x +1) = (4x+1) (3x+4)

=> 12x^2 + 14x + 2 = 12x^2 + 19x + 4

=> 19x -14x = 2 - 4

=> 5x = -2

thus, x = -2/5