Question

If 2x⋅2y⋅2z=128. x,y,z are natural number and x

Answer 1

Answer:

=> 2x . 2y . 2z = 128

» x . y . z = 16

» x . y . z = 1 × 2 × 8

» x . y . z = 1 × 4 × 4

Hence,

Let A be the set of values of x,

A = {x / x = 2^n, 0 ≤ n ≥ 3}