Question

if (2x+3)(2x+a)=4x^2+8x+3 then the value of a is

Answer 1

Answer:

1

Step-by-step explanation:

●(2x+3) (2x+a) = 4x(square) + 8x + 3

●Multiplying the terms of L.H.S.

●2x(2x+a) + 3(2x+a)

●4x(square) + 2ax + 6x + 3a = 4x(square) +8x +3

●By transferring the terms of R.H.S. in L.H.S.

●4x(square) - 4x(square) + 6x-8x + 2ax + 3a =3

●2ax-2x+3a = 3

OR

2ax + 3a - 2x = 3

● Taking common in first two terms of L.H.S. (a)

a(2x+3)-2x = 3

● Transferring 2x in R.H.S.

a(2x+3) = 3+2x

● Transferring 2x+ 3 in R.H.S.

a= (3+2x)÷( 2x+3)

● We can write 3+2x as 2x+3

So,

a = (2x+3)÷(2x+3)

● a = 1. ANS.

I hope this will help you!

Answer 2

Answer:

a=1

Step-by-step explanation

(2x+3)(2x+a)=4x^2+8x+3

(2x)^2+(2x)(a)+(3)(2x)+(3)(a)=4x^2+8x+3

4x^2+2xa+6x+3a=4x^2+8x+3

from both the sides 4x^2 will be cut

therefore,2xa+6x+3a=8x+3

∴2xa+3a=8x-6x+3

∴2xa+3a=2x+3

take a common from 2xa+3a

⇒a(2x+3)=2x+3

∴a=2x+3/2x+3

∴a=1

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