Question

If (2x+3) (3x-1) = 6x²+kx-3 then find k​

Answer 1

Answer:

/*'!6:!9

Step-by-step explanation:

(=:':525554)=55545(/:/:5

Answer 2

Answer:

k = 7

Step-by-step explanation:

(2x + 3) (3x - 1) = 6x² + kx - 3

⇒ 2x(3x - 1) +3(3x - 1) = 6x² + kx - 3

⇒ 6x² - 2x + 9x - 3 = 6x² + kx - 3

⇒ 6x² + 7x - 3 = 6x² + kx - 3

⇒ 6x² - 6x² + 7x - 3 + 3 = kx   [The terms has been transposed]

⇒ 7x = kx

$\implies \frac{7x}{x} = k$

⇒ 7 = k

⇒ k = 7

∴ k = 7

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