if (2x +3) (3x-4) = 6*2 + x + a then the value of ais is
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Answer:
x=2√2a
Step-by-step explanation:
(2x+3) (3x-4)=6*2+x+a
6x*2-8x+9x-12=36+x+a
6x*2-48+a=0
6x*2=48-a
x*2=48-a/6
x*2=8-a
x=√8-a
x=2√2a
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