Math, asked by arjunk5454, 3 months ago

if (2x +3) (3x-4) = 6*2 + x + a then the value of ais is​

Answers

Answered by madhumitamanna00476
0

Answer:

x=2√2a

Step-by-step explanation:

(2x+3) (3x-4)=6*2+x+a

6x*2-8x+9x-12=36+x+a

6x*2-48+a=0

6x*2=48-a

x*2=48-a/6

x*2=8-a

x=√8-a

x=2√2a

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