Question

If 2x^3-7x+8 is divided by x+1, then
remainder is :​

Answer 1

Answer:

hope it helps you......

Answer 2

$\huge\mathfrak\red{Answer:}$

Given:

• We have been given a cubic polynomial.

To Find:

• We need to find the remainder when 2x^3-7x+8 is divided by x+1.

Solution:

We have been given a cubic polynomial 2x^3-7x+8.

On dividing 2x^3-7x+8 by x+1, we get 13 as remainder and the quotient obtained is 2x^2 - 2x - 5.

$\begin{array}{r|cccc} & 2x^2 - 2x-5&\\ \cline{2-5} x+1 & 2x^2 & -7x & +8 \\ & 2x^3& +2x^2& \\ \cline{2-5} & & -2x^2 & -7x & + 8\\ & & -2x^2 & -2x \\ \cline{2-5} & & -5x & +8 \\\\&&-5x&-5\\ \cline{2-5}&&&13\end{array}$