Question

If (2x-3) is a factor of 2x^4-x^3-3x^2-2x+a, then find the value of 'a'. options: a=-3, b=-2, c=2, d=3​

Answer 1

Step-by-step explanation:

2x-3=0

x=3/2

2(3/2)⁴-(3/2)³-3(3/2)²-2(3/2)+a=0

2(81/16)-27/8-3(9/4)-2+a=0

81/8-27/8-27/4-2+a=0

81-27-54-16+8a/8=0

81-27-54-16+8a=0

81-97+8a=0

-16+8a=0

8a=16

a=16/8

a=2