Question

If 2x/3 - y/2 + 1/6 = 0 & x/2 + 2y/3 = 3 then,
(a) x = 2, y = 3
(b) x = -2, y = 3
(c) x = 2, y = -3
(d) x = -2, y = -3

Answer 1

Answer:

The answer is "A"

Step-by-step explanation:

after solving, we will get the equation.

4x-3y+1=0---(1)

3x+4y=18--(2)

Multiply 3 in equation 1 & 4 in equation 2

we get,

12x-9y+3=0

12x+16y=72

after solving this equation,we will get

x=2

y=3

I hope, I helped you.

Answer 2

Option a - x=2 and y=3

Step-by-step explanation:

Given : Equation $\frac{2x}{3}-\frac{y}{2}+\frac{1}{6}=0$ and $\frac{x}{2}+\frac{2y}{3}=3$

To find : Solution of equation ?

Solution :

Re-write the equation as,

$\frac{2x}{3}-\frac{y}{2}=-\frac{1}{6}$

$\frac{4x-3y}{6}=-\frac{1}{6}$

$4x-3y=-1$.....(1)

$\frac{x}{2}+\frac{2y}{3}=3$

$\frac{3x+4y}{6}=3$

$3x+4y=18$ .....(2)

Multiply (1) by 4 and (2) by 3,

$16x-12y=-4$ ......(3)

$9x+12y=54$  ......(4)

Adding equation (3) and (4),

$16x+9x=-4+54$

$25x=50$

$x=2$

Substitute in (1),

$4(2)-3y=-1$

$8-3y=-1$

$3y=9$

$y=3$

Therefore, the solution is x=2 and y=3.

So, option a is correct.

#Learn more

3y = 3/2x + 6 1/2 y –1/4 x = 3

https://brainly.in/question/6562081