If 2x/3 - y/2 + 1/6 = 0 & x/2 + 2y/3 = 3 then,
(a) x = 2, y = 3
(b) x = -2, y = 3
(c) x = 2, y = -3
(d) x = -2, y = -3
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(d) x = -2, y = -3
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