If 2x,3x+1,5xis an Arithmetic sequence.Then,what is the value
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AP = 2X , 3X +1 ,5X
First term (T1) = 2X
Second term (T2) = 3X+1
And,
Third term (T3) = 5X
Common Difference (D) = T2 -T1 = 3X +1 - 2X = X +1
Also,
Common Difference (D) = T3 - T2 = ( 5X ) - ( 3X +1) = 5X - 3X - 1 = 2X -1
As we know that,
Common Difference of an AP is always equal.
So,
T2 - T1 = T3 - T2
X + 1 = 2X -1
2X - X = 1 + 1
X = 2
★ HOPE IT WILL HELP YOU ★
AP = 2X , 3X +1 ,5X
First term (T1) = 2X
Second term (T2) = 3X+1
And,
Third term (T3) = 5X
Common Difference (D) = T2 -T1 = 3X +1 - 2X = X +1
Also,
Common Difference (D) = T3 - T2 = ( 5X ) - ( 3X +1) = 5X - 3X - 1 = 2X -1
As we know that,
Common Difference of an AP is always equal.
So,
T2 - T1 = T3 - T2
X + 1 = 2X -1
2X - X = 1 + 1
X = 2
★ HOPE IT WILL HELP YOU ★
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