Question

if 2x +3y=10 and 3x + 2y= 15, find the value of ( x + y)

plz ans me fast ​

Answer 1

Answer:

5

Step-by-step explanation:

We can solve this by finding x and y.

Hence,

2x+3y=10...(1)

3x+2y=15...(2)

Solving (1) and (2),

$(2x - 3y = 10 ) \times 2\\ (3x + 2y = 15 ) \times 3\\ \\ \\ 4x - 6y = 20 \\ 9x + 6y = 45 \\ 13x = 65 \\ x = \frac{65}{13} \\ x = 5$

Substituting x in (1),

$3x + 2y = 15 \\ 3(5) + 2y = 15 \\ 15 + 2y = 15 \\ 2y = 15 - 15 \\ 2y = 0 \\ y = 0$

y=0

Therefore, (x+y)=5

Answer 2

Answer:

2x +3y=10

3x + 2y= 15

from eq1. 2x +3y=10 can be written as

x = $\frac{10-3y}{2}$

substituting in eq 2

$3x + 2y = 15 \\ 3 ( \frac{10 - 3y}{2} ) + 2y = 15 \\ \frac{30 - 9y}{2} + 2y = 15 \\ \frac{30 - 9y + 4y}{2} = 15 \\ 30 - 9y + 4y = 15 \times 2 \\ - 5y = 0 \\ y = \frac{0}{5} or \: 0$

now value of x =

x = $\frac{10-3y}{2}$

$\frac{10-3(0)}{2}$

$\frac{10}{2}$

x= 5

therefore the value of x is 5 and y is 0

now , ( x + y ) = 0 + 5 = 5