Math, asked by sindri, 1 year ago

if 2x-3y=10 and xy=16 find 8x^3-27y^3

Answers

Answered by piyush887
1
Aq. 2x-3y=10 and xy =16
therefore, let y = 16/x
then 8x^3-27y^3 can be written as
(2x)^3-(3×16/x)^3
(2x)^3-(48/x)^3
8x^3-110529/x^3

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