Math, asked by naina92, 1 year ago

if 2x-3y=10 xy=16 find 8x^3-27y^3

Answers

Answered by siddhartharao77

Given Equation is 2x - 3y = 10 and xy = 16.

On cubing both sides, we get

(2x - 3y)^3 = (10)^3

8x^3 - 27y^3 - 3 * 2x * 3y(2x - 3y) = 1000

8x^3 - 27y^3 - 18xy(2x - 3y) = 1000

8x^3 - 27y^3 - 18(16)(10) = 1000

8x^3 - 27y^3 - 2880 = 1000

8x^3 - 27y^3 = 1000 + 2880

8x^3 - 27y^3 = 3880.

Hope this helps!

siddhartharao77: :-)

naina92: ans zz 3880

naina92: i got the ans thank u

siddhartharao77: could u tell me how u got.

siddhartharao77: Sorry my mistake..i got it

siddhartharao77: I have written 16^3. It should be 10^3.

naina92: yaaa

siddhartharao77: Edited. Done

naina92: thank u

naina92: hey solve my prob

Answered by Anonymous

Hi,

Please see the attached file!

Thanks

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