Question

If 2x+ 3y= 10, xy= 2, find the value of 8x3 +27y3

Answer 1

Answer:

940

Step-by-step explanation:

8x^3 + 27y^3=(2x)^3 + (3y)^3

This is in the form a^3 + b^3 = (a+b)^3 - 3ab(a+b)

=(2x + 3y)^3 - 3(xy)(2x + 3y)

=(10)^3 - 3(2)(10)           (input values from question)

=1000 - 60

=940

hope it helps..

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