Question

if 2x+3y =10and XY=5,find the value of 4x2+9y2​

Answer 1

Answer:

4x2+100Y2−200Y+100

Step-by-step explanation:

Answer 2

Step-by-step explanation:

GIVEN:

2X+3Y=10 AND XY=5

TO FIND:

4X^2+9Y^2

IDENTITY USED:

$({a + b})^{2} = {a}^{2} + {b}^{2} + 2ab$

SOLUTION:

$({2x + 3y})^{2} = ({2x})^{2} + ( {3y})^{2} + 12xy \\ \\ = > {10}^{2} = 4 {x}^{2} + 9 {y}^{2} + 12 \times 5 \\ \\ = > 100 - 60 = 4 {x}^{2} + 9 {y}^{2} \\ \\ = > 40 = 4 {x}^{2} + 9 {y}^{2}$