Math, asked by rushil58, 4 months ago

If 2x+3y=11, what is the value of 4^(x)8^(y)

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Answers

Answered by hansjaiswal47
0

Answer:

hihi idk

Step-by-step explanation:

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Answered by tennetiraj86
2

Answer:

Option B

Step-by-step explanation:

Given :-

2x+3y = 11

To find :-

Find the value of 4^x 8^y ?

Solution :-

Given that

2x+3y = 11 -------------(1)

Now,

4^x 8^y can be written as

=> (2^2)^x × (2^3)^y

=> 2^(2x) × 2^(3y)

Since (a^m)^n = a^(mn)

=> 2^(2x+3y)

It is in the form of a^m × a^n

Where, a = 2 , m = 2x and n = 3y

We know that

a^m × a^n = a^(m+n)

=> 2^11 (from (1))

Answer:-

The value of 4^x 8^y for the given problem is 2^11

Used formulae:-

  • (a^m)^n = a^(mn)
  • a^m × a^n = a^(m+n)
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