If 2x+3y = 12 and xy = 5, find the value of 4x²-9y²
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If 2x+3y = 12 and xy = 5, find the value of 4x²-9y²
Given,
2x+3y= 12 and xy= 5
Squaring both sides:-
(2x-3y)² = 8²
4x²+9y²+2 × 2x × 3y= 64
4x²+9y²+12 × 5= 64
4x²+9y² + 60 = 64
4x²+9y² = 64-60
4x²+9y²= 4
Hence proved:-
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