Question

if 2x+3y=12 and xy=6,
find the value of 8x^3+27y^3​

Answer 1

Answer:

Cubing on both sides.

(2x+3y)^3=12^3

8x^3+27y^3+(3×2x×3y)×(2x+3y)=178

8x^3+27y^3+(18×6×12)=178

8x^3+27y^3=178-1296

= -1118

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