If 2x+3y=12 and xy =6,find the value of 8x3+27y3
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Hii frnd.
Given,
2x+3y=12 and xy=6
From xy=6,we can get the value of either x or y
x=6/y
Now putting the value of x in 2x+3y=12
12/y+3y=12
12+3y^2=12y
3y^2-12y+12=0
On taking 3 common,we will get
y^2-4y+4=0
y^2-2y-2y+4=0
y(y-2)-2(y-2)=0
y=2.
Putting the value of y in xy=6
x=3.
Now put the value of x and y in the que eq.
8*27+27*8
216+216
432
Hope it helped u.
Given,
2x+3y=12 and xy=6
From xy=6,we can get the value of either x or y
x=6/y
Now putting the value of x in 2x+3y=12
12/y+3y=12
12+3y^2=12y
3y^2-12y+12=0
On taking 3 common,we will get
y^2-4y+4=0
y^2-2y-2y+4=0
y(y-2)-2(y-2)=0
y=2.
Putting the value of y in xy=6
x=3.
Now put the value of x and y in the que eq.
8*27+27*8
216+216
432
Hope it helped u.
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