Math, asked by kashishdips01373, 8 months ago

 If 2x+3y=12 and xy=6. Find the value of 8x3+27y3.​

Answers

Answered by shivaranjani1218
15

Step-by-step explanation:

(a+b)³ = a³+b³+3ab(a+b)

8x³+27y³ = (2x+3y)³

(2x+3y)³= (2x)³+(3y)³+3(2x)(3y)[2x+3y]

(12)³ = 8x³+27y³+3(6)(xy)[12]

1728 = 8x³+27y³+18(6)(12)

1728 = 8x³+27y3+1296

1728-1296 = 8x³+27y³

432 = 8x³+27y³

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