If 2x+3y=12 and xy=6. Find the value of 8x3+27y3.
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Step-by-step explanation:
(a+b)³ = a³+b³+3ab(a+b)
8x³+27y³ = (2x+3y)³
(2x+3y)³= (2x)³+(3y)³+3(2x)(3y)[2x+3y]
(12)³ = 8x³+27y³+3(6)(xy)[12]
1728 = 8x³+27y³+18(6)(12)
1728 = 8x³+27y3+1296
1728-1296 = 8x³+27y³
432 = 8x³+27y³
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