if 2x+3y=12 and xy=6, find the value of 8x³+27y³
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Step-by-step explanation:
given 2x+3y=12 and xy=6
on cubing both sides we get
(2x+3y)³=12³
8x³+27y³+3xy(2x+3y) =1728
8x³+27y³+216=1728
8x³+27y³=1512
and (a+b)³=a³+b³+3ab(a+b)
Answered by
6
Answer:
-1512
Step-by-step explanation:
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