Math, asked by Anonymous, 1 year ago

if 2x = 3y = 12 and xy = 6, find the value of 8x³ + 27y³ using substitution method please don't do anya spam answers

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Answered by Anonymous

Answer:

$<body bgcolor="r"><font color="cyan">$

$\huge{\bold{Given}}$

$2x + 3y = 12 \\ \\ xy = 6 \\ \\$

$\huge{\bold{ To \:Find}}$

$8 {x}^{3} + 27{y}^{3}$

$\huge{\bold{ Solution}}$

$cubing \: both \: side \\ \\ {(2x + 3y)}^{3} = {12}^{3} \\ \\ 8 {x}^{3} + 27 {y}^{3} + 18xy(2x + 3y) \\ = 1728\\ \\ 8 {x}^{3} + 27 {y}^{3} + 18 \times 6(12) = 1728 \\ \\ 8 {x}^{3} + 27 {y}^{3} + 1296 = 1728 \\ \\ 8 {x}^{3} + 27 {y}^{3} = 432$

Answered by Anonymous

Answer:

432 is the answer of this question ok

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if 2x = 3y = 12 and xy = 6, find the value of 8x³ + 27y³ using substitution method please don't do anya spam answers​

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if 2x = 3y = 12 and xy = 6, find the value of 8x³ + 27y³ using substitution method please don't do anya spam answers