Math, asked by Anonymous, 9 months ago

if 2x = 3y = 12 and xy = 6, find the value of 8x³ + 27y³ using substitution method please don't do anya spam answers​

Answers

Answered by Anonymous
3

Answer:

<body bgcolor="r"><font color="cyan">

\huge{\bold{Given}}

2x + 3y = 12 \\  \\ xy = 6 \\  \\

\huge{\bold{ To \:Find}}

8 {x}^{3}  + 27{y}^{3}

\huge{\bold{ Solution}}

 cubing \: both \: side \\  \\ {(2x + 3y)}^{3}  =  {12}^{3}  \\  \\ 8 {x}^{3}   + 27 {y}^{3}   + 18xy(2x + 3y)   \\ = 1728\\  \\ 8 {x}^{3}   + 27 {y}^{3}  + 18 \times 6(12) = 1728 \\  \\  8 {x}^{3}   + 27 {y}^{3}   + 1296 = 1728 \\  \\  8 {x}^{3}   + 27 {y}^{3}   = 432

Answered by Anonymous
12

Answer:

432 is the answer of this question ok

Similar questions