If 2x+3y = 12 or xy= 6 find the value of 8x^3+27y^3?
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18
Answer:
432
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Step-by-step explanation:
8x³ + 27y³
= (2x)³ + (3y)³
a³+b³ = (a+b)(a²+b²-ab)
a³+b³ = (a+b)( (a+b)²-3ab)
a = 2x & b = 3y
(2x+3y)( (2x+3y)² - 3(2x)(3y) )
= 12 ( 12² - 18xy )
= 12 ( 144 - 18*6)
= 12 (144 - 108)
= 12 * 36
= 432
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