If 2x+3y=12,xy=6, find 8xcube +27ycube
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8x³+27y³
=(2x)³+(3y)³
=(2x+3y)³-3(2x)(3y)(2x+3y)
=(13)³-3(6xy)(13)
=2197-36(6×6)
=2167-36(36)
=2167-1296
=871
=(2x)³+(3y)³
=(2x+3y)³-3(2x)(3y)(2x+3y)
=(13)³-3(6xy)(13)
=2197-36(6×6)
=2167-36(36)
=2167-1296
=871
Answered by
1
hope it helps you........
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