If 2x=3y=12z, show that 1/z=1/y+2/x
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2x=3y=12z=K
2=Kx1,3=Ky1,12=Kz1
2x=K & 3y=K & 12z=K
Apply log on both sides.
xlog2=logkylog3=logkzlog12=logk
x1=logklog2y1=logklog3z1=logklog12
x1=lo
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