Question

If 2x+ 3y= 13 and xy= 6 find the value of 8x^3+27y^3

Answer 1

Answer:

8x^3+27x^3=65

Step-by-step explanation:

Cubing both sides:-

(2x+3y)^3=(13)^3

(2x)^3+(3y)^3+3xy(2x+3y)=169

8x^3+27y^3+3*6*13=169

8x^3+27y^3=169-234

8x^3+27y^3= 65