Question

✿If 2x+3y = 13 and XY = 6,find the value of 8x^3+27y^3..

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Answer 1

Answer:

8x^3+27y^3

(2x)^3+(3y)^3

(2x+3y)^3-3(2x)(3y)(2x+3y)

(13)^3-3(6xy)(13)

2197-3{6(6)}(13)

2197-3×36×13

2197-3×468

2197- 1404

397

Answer 2

ANswer

ᴡᴇ ʜᴀᴠᴇ,

(2x+3ʏ)^3 = (2x)^3 + (3ʏ)^3 + 3(2x)(3ʏ)(2x+3ʏ)

➠(2+3)= 8x^3+27ʏ^3+18xʏ(2x+3ʏ)

➠(13)^3 = 8x^3+27ʏ^3 + 18(6)(13)

➠2197 = 8x^3+27ʏ^3+1401

➠8x^3+27ʏ^3

➠2197-1404

➠793